FIDE Chess World Cup 2025 Round 4 Tiebreaks Results and Standings LIVE Updates: After Pranav V and Karthik Venkataraman were eliminated during Game 2 of Round 4 of the ongoing FIDE Chess World Cup 2025, taking place in Goa, only three Indians are left in the fray for the title race.
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José Eduardo Martínez Alcántara, Levon Aronian, Alexander Donchenko, Le Quan Liem and Nodirbek Yakubboev have already qualified for the next round, while 11 boards and 22 players will fight it out via tiebreaks.
An unprecedented 24 Indian players entered the FIDE World Cup, but over four rounds, 21 have been eliminated. The first round saw seven Indian players knocked out, followed by another seven in the second round. The third round witnessed the exit of five more, including top seed D. Gukesh and former Candidates player Vidit Gujrathi.
The top three finishers in the 2025 World Cup will secure a place in the 2026 Candidates Tournament in Cyprus. The winner of that event will earn the right to challenge the reigning World Champion.
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FIDE World Cup: Undeterred by Vladimir Kramnik’s cheating allegations, José Eduardo Martínez Alcántara making a big impact in Goa
José Eduardo Martínez Alcántara played Vladimir Kramnik in Clash of Blames event. (Photo: World Chess)
The odds were always stacked against Martínez Alcántara. A win would only have proved that his current form was better than Kramnik’s, but the shadow of doubt would linger regardless. A loss, however, would have severely hurt his reputation. Yet, he chose to withstand an opponent whose obsession with “cheating in chess” has put the sport in a crisis.
Moving forward, Martínez Alcántara chose the simplest path: to grind his way up in both online and OTB chess, and is reaping the rewards. At the ongoing FIDE Chess World Cup in Goa, he has impressed with his serene progress.
